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Area bounded by y=sec^-1x,y=cot^-1x and ...

Area bounded by `y=sec^-1x`,`y=cot^-1x` and line x=1 is given by

A

`log(3+2sqrt(2))-(pi)/(2)` sq. units

B

`(pi)/(2)-log (3+2sqrt(2))` sq. units

C

`pi-log_(e)3` sq. units

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A


Integrating along x-axis, we get
`A=overset(sqrt(2))underset(1)int(cosec ^(-1)x-sec^(-1)x) dx`
Integrating along y-axis, we get
`A=2overset(pi//6)underset(0)int(sec y-1)dy`
`=2[ log |sec y + tan y|-y]_(0)^(pi//4)`
`=2[log |sqrt(2)+1|-(pi)/(2)]`
`=log (3+2sqrt(2))-(pi)/(2)` sq. units.
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