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Number of values of alpha such that the ...

Number of values of `alpha` such that the points `(alpha,6),(-5,0)` and (5,0) form an isosceles triangle is

A

4

B

5

C

6

D

7

Text Solution

Verified by Experts

The correct Answer is:
B
We have `A(alpha,6), B(-5,0)` and `C(5,0)`
If `AB =AC`, we get `alpha = 0`. Hence, we get one value of c If `AC = BC`, we get `alpha = - 3,13`
`alpha` can take 5 units: `0,3,-3,13,-13`
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