The incentre of a triangle with vertices `(7, 1),(-1, 5)` and `(3+2sqrt(3),3+4sqrt(3))` is
A
`(3+(2)/(sqrt(3)),3+(4)/(sqrt(3)))`
B
`(1+(2)/(3sqrt(3)),1+(4)/(3sqrt(3)))`
C
`(7,1)`
D
None of these
Text Solution
Verified by Experts
The correct Answer is:
A
`:' AB = BC = CA =4sqrt(5)` i.e., given triangle is equilateral. Hence, incentre `= ((7-1+3+2sqrt(3))/(3),(1+5+3+4sqrt(3))/(3))` (centroid) `=(3+(2)/(sqrt(3)),3+(4)/(sqrt(3)))`
The triangle with vertices (2,4), (2,6) and (2+ sqrt(3) ,5) is
The incentre of triangle with vertices (1, sqrt(3)), (0,0) and (2, 0) is
The incetre of the triangle with vertices (1,sqrt(3)),(0,0) and (2,0) is
Inradius of the triangle with vertices (1,1), (-1,-1), (-sqrt3, sqrt3) is
Find the incentre of the triangle with vertices (1,sqrt(3)),(0,0) and (2,0)
The incenter of the triangle with vertices (1,sqrt(3)),(0,0), and (2,0) is (a) (1,(sqrt(3))/(2)) (b) ((2)/(3),(1)/(sqrt(3)))(c)((2)/(3),(sqrt(3))/(2)) (d) (1,(1)/(sqrt(3)))
(1)/(4sqrt(3)-3sqrt(5))
CENGAGE-COORDINATE SYSTEM-Multiple Correct Answers Type
