Keeping coordinate axes parallel, the origin is shifted to a point (1, –2), then transformed equation of x^2 + y^2 = 2 is -
When the origin is shifted to the point (5,-2) then the transformed equation of the curve xy+2x-5y+11=0 is XY=K then k is
If origin is shifted to the point (-1,2) then what will be the transformed equation of the curve 2x^(2)+y^(2)-3x+4y-1=0 in the new axes ?
When (0,0) shifted to (2,-2) the transformed equation of (x-2)^(2)+(y+2)^(2)=9 is
When the origin is shifted to (2,3) then the original equation of x^(2)+y^(2)+4x+6y+12=0 is
If origin is shifted to the point (a,b) then what will be the transformed equation of the curve (x-a)^(2)+(y-b)^(2)=r^(2) ?
If origin is shifted to the point (2,3) then what will be the transformed equation of the straight line 2x-y+5=0 in the new XY -axes ?
Find the point at which origin is shifted such that the transformed equation of x^(2)+2y^(2)-4x+4y-2=0 has no first degree term. Also find the transformed equation .
Find the transformed equation of the curve y^(2)-4x+4y+8=0 when the origin is shifted to (1,-2) .
CENGAGE-COORDINATE SYSTEM-Multiple Correct Answers Type