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Let A(a,0) and B(b,0) be fixed distinct ...

Let `A(a,0) and B(b,0)` be fixed distinct points on the x-axis, none of which coincides with the `O(0,0)`, and let C be a point on the y-axis. Let L be a line through the `O(0,0)` and perpendicular to the line AC. The locus of the point of intersection of the lines L and BC if C varies along is (provided `c^2 +ab != 0`)

A

`(x^(2))/(a)+(y^(2))/(b) =x`

B

`(x^(2))/(a)+(y^(2))/(b) =y`

C

`(x^(2))/(b)+(y^(2))/(a)=x`

D

`(x^(2))/(b)+(y^(2))/(a) =y`

Text Solution

Verified by Experts

The correct Answer is:
C
Equation of the line L is `y = (a)/(c)x`
As (h,k) lies on it, hence
`k = (a)/(c )h` (i)
Now equation of BC
`(x)/(b)+(y)/(c ) =1`
(h,k) lies on it
`:. (h)/(b) +(k)/(c ) = 1`

Substituting `c = (ah)/(k)` in (ii) from (i)
`(h^(2))/(hb) +(k^(2))/(ah) =1`
`:.` Locus of P is `(x^(2))/(b) +(y^(2))/(a) = x`
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