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The equation of the diagonal of the squa...

The equation of the diagonal of the square formed by the pairs of lines `xy +4x - 3y - 12 = 0` and `xy - 3x +4 y - 12 = 0` is

A

`x - y = 0`

B

`x +y +1 = 0`

C

`x +y = 0`

D

`x - y +1 = 0`

Text Solution

Verified by Experts

The correct Answer is:
A, B
`xy +4x -3y -12 =0`
`rArr (x-3) (y+4) =0`
`xy -3x +4y -12 =0`
`rArr (x-4) (y-3) =0`
The vertices are
`A =(-4,-4), B =(-4,3), C =(3,3), D =(3,-4)`
Diagonal AC is `x =y` and diagonal BD is `x +y +1 = 0`.
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