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Let P(alpha,beta) be a point in the firs...

Let `P(alpha,beta)` be a point in the first quadrant. Circles are drawn through P touching the coordinate axes.
Radius of one of the circles is

A

`(sqrt(a)-sqrt(beta))^(2)`

B

`(sqrt(alpha)+sqrt(beta))^(2)`

C

`alpha +beta -sqrt(alpha beta)`

D

`alpha +beta -sqrt(2alpha beta)`

Text Solution

Verified by Experts

The correct Answer is:
D

Let equation of circle be `(x-r)^(2) + (y-r)^(2) = r^(2)`
`rArr x^(2) +y^(2) -2r (x+y) +r^(2) =0`, where r is radius of circle which is passing through `(alpha, beta)` so
`alpha^(2) + beta^(2) -2r (alpha +beta) +r^(2) =0`
`rArr r = (2(alpha+beta)+-sqrt(4(alpha+beta)^(2)-4(alpha^(2)+beta^(2))))/(2)`
`rArr r = (alpha + beta) +- sqrt(2 alpha beta)`
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