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The distance of the focus of x^(2)-y^(2)...

The distance of the focus of `x^(2)-y^(2) =4`, from the directrix, which is nearer to it, is

A

`2sqrt(2)`

B

`sqrt(2)`

C

`4sqrt(2)`

D

`8sqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`x^(2) -y^(2) =4` is rectangular hyperbola.
`:. e = sqrt(2)`
Required distance `= ae - a//e = 2 sqrt(2) -2//sqrt(2) = sqrt(2)`
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