Dertermine the current through the battery of internal resistance `0.5 Omega` for the circuit shown in fig. `7.14`. How much power is dissipated in `6 omega` resistance ?

Calculate the current drawn from the battery of emf 15V and internal resistance 0.5Omega in the circuit shown in Fig. 6.12. Also find the power dissipated in thd 6Omega resistor.

In the circuit shown the current through 2 Omega resistance is

A battery of unknown emf and internal resistance is given to a student for the experiment. When student connects the battery to an external resistance of 10 Omega then 1A current flows through the circuit and when the same is connected to 15 Omega resistance then 0.75 A current flows through the circuit . Calculate the emf and internal resistance of the given battery.

The power dissipated in 3 Omega resistance in the following circuit is

A 5 V battery with internal resistance 1 Omega and a 2 V battery with internal resistance 0.5 Omega are connected to a 3 Omega resistor as shown in the figure.The current in the 3 Omega resistor is

A 5 V battery with internal resistance 2Omega and a 2V battery with internal resistance 1Omega are connected to a 10Omega as shown in the figure. The current in the 10Omega resistance is

The circuit diagram in Fig. shows three resistors 2 Omega , 4 Omega and R Omega connected to a battery of e.m.f. 2 V and internal resistance 3 Omega . If current of 0.25 A flows through the circuit, find : the p.d. across the internal resistance of the cell,