Show that the function `f(x)=x^2+3x+5`,is continuos at x=1.

Explanation

To show that the function \( f(x) = x^2 + 3x + 5 \) is continuous at \( x = 1 \), we need to verify that:

1. The function \( f(1) \) is defined.
2. The limit of \( f(x) \) as \( x \) approaches 1 exists.
3. The limit of \( f(x) \) as \( x \) approaches 1 is equal to \( f(1) \).

### Step 1: Calculate \( f(1) \)

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