If `f(x)={(x^3+x^2-16x+20)/(x-2)^2,x ne 0`
k, x=0 is continuous for all real values of x, find the value of K.

Explanation

To find the value of \( k \) such that the function

\[
f(x) =
\begin{cases}
\frac{x^3 + x^2 - 16x + 20}{(x-2)^2} & \text{if } x \neq 0 \\
k & \text{if } x = 0
\end{cases}
...