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If x^4+y^4-a^2xy=0 " then find " dy/dx...

If `x^4+y^4-a^2xy=0 " then find " dy/dx`

A

`dy/dx =(a^2-4x^3)/(4y^3-a^2x)`

B

`dy/dx =(a^2y-x^3)/(4y^3-a^2x)`

C

`dy/dx =(a^2y-4x^3)/(y^3-a^2x)`

D

`dy/dx =(a^2y-4x^3)/(4y^3-a^2x)`

Text Solution

Verified by Experts

The correct Answer is:
D

`x^4+y^4-a^2xy=0 `
`4x^3+4y^3 dy/dx`
`4x^3+4y^3 dy/dx-a^2(xdy/dx+y.1)=0`
`rArr 4x^3 +3y^3dy/dx-a^2xdy/dxa^2y=0`
`rArr dy/dx(4y^3-a^3x)=a^2y-4x^3`
`rArr dy/dx =(a^2y-4x^3)/(4y^3-a^2x)`
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NAGEEN PRAKASHAN-Continuity and Differentiability-Miscellaneous Exercise
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