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Discuss the continuity of f(x) ={:{(cos"...

Discuss the continuity of `f(x) ={:{(cos""(1)/(x)", "x ne 0),(" "1", " x= 0):},`

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To discuss the continuity of the function \( f(x) \) defined as: \[ f(x) = \begin{cases} \cos\left(\frac{1}{x}\right) & \text{if } x \neq 0 \\ 1 & \text{if } x = 0 \end{cases} \] we will follow these steps: ### Step 1: Identify the points of interest We need to check the continuity of \( f(x) \) at \( x = 0 \) since the function is defined differently at this point compared to other values of \( x \). **Hint:** Continuity at a point requires that the limit of the function as \( x \) approaches that point equals the function's value at that point. ### Step 2: Calculate the limit as \( x \) approaches 0 We need to find: \[ \lim_{x \to 0} f(x) = \lim_{x \to 0} \cos\left(\frac{1}{x}\right) \] As \( x \) approaches 0, \( \frac{1}{x} \) approaches infinity. Therefore, we can rewrite the limit: \[ \lim_{x \to 0} \cos\left(\frac{1}{x}\right) = \lim_{t \to \infty} \cos(t) \quad \text{(where } t = \frac{1}{x}\text{)} \] **Hint:** The cosine function oscillates between -1 and 1 as its argument approaches infinity. ### Step 3: Analyze the limit The limit \( \lim_{t \to \infty} \cos(t) \) does not exist because the cosine function does not settle at any particular value; it keeps oscillating. **Hint:** If a limit does not exist, it cannot equal a specific value. ### Step 4: Compare the limit with the function value at \( x = 0 \) We know that: \[ f(0) = 1 \] Since the limit as \( x \) approaches 0 does not exist, we conclude that: \[ \lim_{x \to 0} f(x) \neq f(0) \] **Hint:** For continuity, we need \( \lim_{x \to a} f(x) = f(a) \). Here, it fails. ### Step 5: Conclusion about continuity Since the limit does not exist and does not equal \( f(0) \), we conclude that the function \( f(x) \) is not continuous at \( x = 0 \). **Final Statement:** The function \( f(x) \) is not continuous at \( x = 0 \). ### Summary of Steps: 1. Identify points of interest (check continuity at \( x = 0 \)). 2. Calculate the limit as \( x \) approaches 0. 3. Analyze the limit (it does not exist). 4. Compare the limit with the function value at \( x = 0 \). 5. Conclude about continuity.
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NAGEEN PRAKASHAN-Continuity and Differentiability-Exercies 5a
  1. Discuss the continuiy of the function f(x)={(1/x ", " x ne 0),(1...

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  2. Discuss the continuity of the function f(x)={((|x|)/x", " xne 0)...

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  3. (i) Dissusse the continuity of the function f(x)={(|x-a|", " xne a...

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  4. Show that f(x) = sinx is continuous for all values of x.

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  5. Prove that f(x) = {sinx/x ; x != 0 and 1 ; x=0. is continuous at x=0...

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  6. If f(x) ={:{((sin 3x)/(sin 5x)", "x ne 0),(0", " x= 0):}, then d...

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  7. Show that the function f(x) ={:{((sin 3x)/(x)", "x ne 0),(1", " ...

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  8. Discuss the continuity of f(x) ={:{((sin^2 2x)/(x^2)", "x ne 0),(1", ...

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  9. Discuss the continuity of f(x) ={:{(cos""(1)/(x)", "x ne 0),(" "1",...

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  10. Discuss the continuity of f(x) ={:{(sin""(1)/(x)", "x ne 0),(" "1", ...

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  11. Discuss the continutiy of f(x) ={:{(xcos""(1)/(x)", "x ne 0),(" "0...

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  12. Disuss the continutiy of f(x) ={:{((sin^2 x)/(x^2)", "x ne 0),(" "0"...

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  13. If the function f(x) ={:{((3x^3-2x^2-1)/(x-1)", "x ne 1),(" "K", ...

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  14. For what value of k, the function f(x) ={:{(Kx^2", " x le 2 ),(" ...

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  15. For what value of k, the function f(x) ={:{((x^2-4)/(x-2)", " x ne 2...

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  16. For what value of k, the function f(x) ={:{(2x+1", "x gt2),(" ...

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  17. If the function f(x) given by f(x)={(3a x+b,"if "x >1), (11,"if "x=1),...

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  18. Discuss the continuity of the function f(x) ={:{((1+cos x)/(tan^2 x...

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  19. Discuss the continuity of the function f(x) ={:{((Sinx)/(x) ", "x ...

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  20. Prove that the function f(x)=2x-|x| is continuous at x=0.

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