`sin^4x`

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To find the derivative of the function \( f(x) = \sin^4 x \), we will use the chain rule. Here’s a step-by-step solution: ### Step 1: Identify the outer and inner functions The function can be expressed as: \[ f(x) = (\sin x)^4 \] Here, the outer function is \( u^4 \) where \( u = \sin x \), and the inner function is \( \sin x \). ### Step 2: Differentiate the outer function Using the power rule, the derivative of \( u^n \) is \( n \cdot u^{n-1} \). Therefore, the derivative of \( u^4 \) is: \[ \frac{d}{du}(u^4) = 4u^3 \] ### Step 3: Differentiate the inner function The derivative of \( \sin x \) is: \[ \frac{d}{dx}(\sin x) = \cos x \] ### Step 4: Apply the chain rule According to the chain rule: \[ f'(x) = \frac{d}{du}(u^4) \cdot \frac{d}{dx}(\sin x) \] Substituting the derivatives we found: \[ f'(x) = 4(\sin x)^3 \cdot \cos x \] ### Step 5: Write the final answer Thus, the derivative of \( f(x) = \sin^4 x \) is: \[ f'(x) = 4 \sin^3 x \cos x \] ---
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