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e^("sin x")...

`e^("sin x")`

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To differentiate the function \( e^{\sin x} \), we will use the chain rule. The chain rule states that if you have a composite function \( f(g(x)) \), then the derivative is given by \( f'(g(x)) \cdot g'(x) \). ### Step-by-Step Solution: 1. **Identify the outer and inner functions**: - Let \( u = \sin x \) (inner function). - Then, the function can be rewritten as \( e^u \) (outer function). 2. **Differentiate the outer function**: - The derivative of \( e^u \) with respect to \( u \) is \( e^u \). 3. **Differentiate the inner function**: - The derivative of \( \sin x \) with respect to \( x \) is \( \cos x \). 4. **Apply the chain rule**: - According to the chain rule, the derivative of \( e^{\sin x} \) is: \[ \frac{d}{dx}(e^{\sin x}) = e^{\sin x} \cdot \frac{d}{dx}(\sin x) = e^{\sin x} \cdot \cos x \] 5. **Write the final answer**: - Therefore, the derivative of \( e^{\sin x} \) is: \[ \frac{d}{dx}(e^{\sin x}) = \cos x \cdot e^{\sin x} \] ### Final Answer: \[ \frac{d}{dx}(e^{\sin x}) = \cos x \cdot e^{\sin x} \]
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