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y=(tanx)^(logx)+(cosx)^(sinx)...

`y=(tanx)^(logx)+(cosx)^(sinx)`

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Verified by Experts

The correct Answer is:
`(tanx)^(logx)[(logx)/(sinxcosx)+(logtanx)/x]+(cosx)^(sinx)[cosxlog(cosx)-sinxcdottanx]`
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