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x = "sin" t, y = "cos" 2t...

`x = "sin" t, y = "cos" 2t`

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To solve the given problem, we need to find the value of \(\frac{dy}{dx}\) and then the second derivative \(\frac{d^2y}{dx^2}\) for the parametric equations \(x = \sin t\) and \(y = \cos 2t\). ### Step-by-Step Solution: 1. **Find \(\frac{dx}{dt}\)**: \[ x = \sin t \quad \Rightarrow \quad \frac{dx}{dt} = \cos t \] ...
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