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if x=a(costheta+thetasintheta) , y=a(si...

if `x=a(costheta+thetasintheta) , y=a(sintheta-thetacostheta)` then `(d^2y)/(dx^2)`

Text Solution

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`x=a("cos" theta + theta "sin" theta)`
`rArr (dx)/(d theta) = a(-"sin" theta + theta "cos" theta + "sin" theta)=a theta "cos" theta`
`"and " y = a("sin" theta - theta "cos" theta)`
`rArr (dy)/(d theta) = a["cos" theta- (-theta "sin" theta + "cos" theta)]=a theta "sin" theta`
`"Now " (dy)/(dx) = (dy//d theta)/(dx//d theta) = (a theta "sin" theta)/(a theta "cos" theta) = "tan" theta`
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