`x*cos x`

Text Solution

AI Generated Solution

To find the second order derivative of the function \( y = x \cos x \), we will follow these steps: ### Step 1: Differentiate the function \( y = x \cos x \) Using the product rule for differentiation, which states that if \( y = u \cdot v \), then \( \frac{dy}{dx} = u'v + uv' \), we can identify: - \( u = x \) and \( v = \cos x \) - Thus, \( u' = 1 \) and \( v' = -\sin x \) ...
Promotional Banner

Topper's Solved these Questions

  • Continuity and Differentiability

    NAGEEN PRAKASHAN|Exercise Exercies 5.8|6 Videos

  • Continuity and Differentiability

    NAGEEN PRAKASHAN|Exercise Miscellaneous Exercise|23 Videos

  • Continuity and Differentiability

    NAGEEN PRAKASHAN|Exercise Exercies 5.6|11 Videos

  • APPLICATIONS OF INTEGRALS

    NAGEEN PRAKASHAN|Exercise Miscellaneous Exercise|19 Videos

  • DETERMINANTS

    NAGEEN PRAKASHAN|Exercise Miscellaneous Exercise|19 Videos

Similar Questions

Explore conceptually related problems

Prove that 1 + cos 2x + cos 4x + cos 6x = 4 cos x *cos 2x *cos 3x .

Prove that: 1+cos2x+cos4x+cos6x=4cos x cos2x cos3x

The period of function f(x)=(sin x+cos3x+cos4x+|cos4x|+|cos x|) is equal to

The product ("cos"(x)/(2))*("cos"(x)/(4))*("cos"(x)/(8))* * * * * * * * ("cos"(x)/(256)) is equal to :

(cos x)/(1-sin x)=(1+cos x+sin x)/(1+cos x-sin x)

lim_(x->0) (cos2x-cos4x)/(cos3x-cos5x) =

(sin x)/(sin x)=lambda cos(x)/(8)-cos(x)/(4)cos(x)/(2), then lambda =

intcos.(x)/(16)cos.(x)/(8)cos.(x)/(4)cos.(x)/(2)sin.(x)/(16)dx=