In `Delta ABC`, the side c and angle C are constant. If there are small changes in the remaining sides and angles, then show that
`(da)/(cos A) +(db)/(cos B)= 0`.

Explanation

We know that
`a/(sin A) = b/(sin B) = c/(sin C)`
But c and C are constant.
Therefore `a/(sin A)= b/(sin B) = k`
` rArr a=k sin A and b=k sin B`
` rArr (da)/(dA) = k cos A and (db)/(dB) k cos B`
`rArr (da)/(cos A) = k * dA and (db)/(cos B) = k * dB`
`rArr (da)/(cos A) + (db)/(cos B) = k(dA+ dB)`
` = k d (A+B) - k d (pi - C)`
` = k * (0)`
`=0`
` :. (da)/(cos A) + (db)/(cos B) = 0`.
`(:( x-2,x gt 2),(2-x,x lt 2):)`