Find the equation of tangent of the curve `6y=9-3x^(2)` at point (1,1).

Explanation

` 6y = 9-3x^(2)`
`rArr 6(dy)/(dx) = 0- 6x`
`rArr (dy)/(dx) =-x`
At point (1, 1), the slope of tangent
m =- 1
Now equation of tangent at point (1, 1) is
` y-1=-1(x-1)`
`rArr x+ y =2`.