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Find the equation of normal to the curv...

Find the equation of normal to the curve `x = a cos^(3)theta, y=b sin^(3) theta" at point "'theta'.`

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The correct Answer is:
`bt sin theta - ax cos theta = b^(2) sin^(4) theta - a^(2) cos^(4) theta`
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NAGEEN PRAKASHAN-APPLICATIONS OF DERIVATIVES-Exercise 6e
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