Find the equation of normal of the curve...

Find the equation of normal of the curve `2y= 7x - 5x^(2)` at those points at which the curve intersects the line x = y.

Verified by Experts

The correct Answer is:

`2x+7y =0, 3x-2y = 1`

APPLICATIONS OF DERIVATIVES
NAGEEN PRAKASHAN|Exercise Exercise 6f|19 Videos
APPLICATIONS OF DERIVATIVES
NAGEEN PRAKASHAN|Exercise Exercise 6g|21 Videos
APPLICATIONS OF DERIVATIVES
NAGEEN PRAKASHAN|Exercise Exercise 6d|24 Videos
APPLICATIONS OF INTEGRALS
NAGEEN PRAKASHAN|Exercise Miscellaneous Exercise|19 Videos

Similar Questions

Explore conceptually related problems

The equation of normal to the curve y^(2)=8x is

Find the equation of normal to the curve x = at^(2), y=2at at point 't'.

Find the equation of normal to the curve y(x-2)(x-3)-x+7=0 at that point at which the curve meets X-axis.

Find the equation of the normal to the curve y=|x^(2)-|x||atx=-2

The equation of normal to the curve y= x ^(2) + 2 at point (1,1) is :

The equation of the normal to the curve y=x(2-x) at the point (2, 0) is

The equation of the normal to the curve y= e^(-2|x|) at the point where the curve cuts the line x=-(1)/(2), is

The equation of the normal to the curve y=e^(-2|x|) at the point where the curve cuts the line x = 1//2 is

Equation of the normal to the curve y=-sqrt(x)+2 at the point (1,1)