Home
Class 12
MATHS
Find minimum value of px+qy where p>0, q...

Find minimum value of `px+qy` where `p>0, q>0, x>0, y>0` when `xy=r,^2` without using derivatives.

A

`pqsqrtr`

B

`2pqsqrtr`

C

`2rsqrtpq`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • APPLICATIONS OF DERIVATIVES

    NAGEEN PRAKASHAN|Exercise Exercise 6.1|18 Videos

  • APPLICATIONS OF DERIVATIVES

    NAGEEN PRAKASHAN|Exercise Exercise 6.2|19 Videos

  • APPLICATIONS OF DERIVATIVES

    NAGEEN PRAKASHAN|Exercise Exercise 6h (multiple Choice Questions)|10 Videos

  • APPLICATIONS OF INTEGRALS

    NAGEEN PRAKASHAN|Exercise Miscellaneous Exercise|19 Videos

Similar Questions

Explore conceptually related problems

The minimum value of the expression 3x + 2y (AA x, y >0) , where xy^(2) = 10 , occurs when the value of y is equal to

If minimum value of x^(2)-2px+p^(2)-1 is equal to 3AA x>=0 then p cannot be

Let f(x)=x^(2)+2px+2q^(2) and g(x)=-x^(2)-2px+p^(2) (where q ne0 ). If x in R and the minimum value of f(x) is equal to the maximum value of g(x) , then the value of (p^(2))/(q^(2)) is equal to

Find the value of p so that the three lines 3x+y-2=0px+2y-3=0 and may intersect at one point.

Three lines px+qy+r=0 , qx+ry+p=0 and rx+py+q=0 are concurrent , if

If the quadratic equation x^(2)-px+q=0 where p, q are the prime numbers has integer solutions, then minimum value of p^(2)-q^(2) is equal to _________

The lines px+qy+r=0,qx+ry+p=0,rx+py+q=0 are concurrant then