The normal at the point `(1,1)` on the curve `2y+x^2=3` is

Options

A. x+y=0
B. x-y= 0
C. x+y+1=0
D. x-y=1

Answer

B

Explanation

Given curve,
` 2y+x^(2)=3`
` rArr 2(dy)/(dx) + 2x - 0 rArr (dy)/(dx) - " "-x`
`:. ` slope of tangent at point (1, 1) =- 1
` rArr" slope of normal at "(1, 1) = (-1)/(((dy)/(dx))_(1, 1)) = (-1)/(-1) = 1`
` :. " equation of normal at "(1, 1) y-1=1*(x-1)`
` rArr x-y=0`