The plane `x / 2 + y / 3 + z / 4 = 1` cuts the co-ordinate axes in `A, B, C`: then the area of the `DeltaABC` is

If the plane x/2+y/3+z/4=1 cuts the coordinate axes in A, B,C, then the area of triangle ABC is

If the plane x/2+y/3+z/4=1 cuts the coordinate axes in A, B,C, then the area of triangle ABC is

If the plane x/2+y/3+z/4=1 cuts the coordinate axes in A, B,C, then the area of triangle ABC is

If the plane (x)/(2)+(y)/(3)+(z)/(4)=1 cuts the coordinate axes in A,B,C, then the area of triangle ABC is

The plane x/2+y/3+z/4 = 1 cuts the axes A, B, C then the area of the triangle ABC is

The plane x/4 + y/3 -z/5 =1 cuts the axes at A, B, C then the area of the triangle ABC is

The plane 2x+3y+4z=1 meets the coordinate axis in A, B, C. The centroid of the DeltaABC is

If the plane x/1 + y/2 + z/3=1 meets the co-ordinate axes in the points A, B and C, then area of triangleABC in sq. units is

If the plane 3x-2y-z-18=0 meets the coordinate axes in A,B,C then, the centroid of DeltaABC is

If the plane 3x+4y-3z+2=0 cuts the coordinate axes at A, B, C, then the centroid of the triangle ABC is