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One faraday of charge was passed through...

One faraday of charge was passed through the electrolytic cells placed in series containing solution of `Ag^(+), Ni^(2+) " and " Cr^(3+)` respectively. The amount of Ag (At. mass 108), Ni (At. mass 50) and Cr(At. mass 52) deposited will be:

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0.1 Faraday of current was passed through the electrolytic cell placed in series containing solutions of Ag^(+), Ni^(2+) and Cr^(3+) respectively. The amount of Ag, Ni and Cr deposited will be (at. Mass, Ag=108, Ni=59, Cr=52 )

One Faraday charge was passed through the electrolytic cell placed in series containing solutions of Ag^(+), Ni^(2+) and Cr^(3+) . Then Ag, Ni and Cr deposited will be (Atomic masses , Ag= 108, Ni = 59 and Cr = 52)

On passing 1 Faraday charge through the electrolytic cells containing Ag^(+),Ni^(2+),Cr^(3+) ions solution, the mass of deposited Ag is (At mass = 108 u ), Ni (At mass = 59u) and Cr (At mass = 52U):

On passing one faraday of elecricity throuth the electrolytic cells containing Ag^+ , Ni^(+3) and Cr^(+3) ion solutions, the deposited Ag (AT. Wt. = 108) Ni (At. Wt = 59 ) and Cr (At wt. = 52) is .

3 faraday electricity was passed through the three electrolytic cells connected in series containing Ag^(+)Ca^(2+) and Al^(+3) ions respectively. The molar ration in which the three metl ions are liberated at the electrodes is :

On passing 3 faraday of electricity through the three electrolytic cells connected in series containing Ag^+ , Ca^(2+) and Al^(3+) ions respectively. The molar ratio in which the three metal ions are liberated at the electron is

On passing 3 faraday of electricity through the three electrolytic cells connected in series containing Ag^+,Ca^(2+) and AI^(3+) ions respectively. The molar ratio in which the three metal ions are liberated at the electrodes is :