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If (cosx-cosalpha)/(cosx-cosbeta)=(sin^2...

If `(cosx-cosalpha)/(cosx-cosbeta)=(sin^2alphacosbeta)/(sin^2betacosalpha)` then `cos x=`

A

`cosx = (cosalpha + cosbeta)/(1+cosalphacosbeta)`

B

`cosx = (cosalpha + cosbeta)/(1-cosalphacosbeta)`

C

`tan 'x/2 = tan'(alpha)/(beta) tan'(beta)/(2)`

D

`tan'x/2 = 3 tan'(alpha)/(2) tan'(beta)/(2)`

Text Solution

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The correct Answer is:
A
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