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If sum(r=1)^(n) r(r+1) = ((n+a)(n+b)(n+c...

If `sum_(r=1)^(n) r(r+1) = ((n+a)(n+b)(n+c))/(3)`, where `a gt b gt c`, then

A

`2b = c`

B

`a^(3)-8b^(3)+c^(3) = 8abc`

C

a is prime number

D

`(a-2b)^(2) = 0`

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The correct Answer is:
A
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