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If sum(n=1)^(2013)tan(theta/(2^(n)))sec(...

If `sum_(n=1)^(2013)tan(theta/(2^(n)))sec((theta)/(2^(n-1))) = tan((theta)/(2^(a)))-tan((theta)/(2^(b)))` then `(b+a)` equals

A

2014

B

2012

C

2013

D

2014

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A
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