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Let f(r) = sum(j=2)^(2008) (1)/(j^(r)) =...

Let `f(r) = sum_(j=2)^(2008) (1)/(j^(r)) = (1)/(2^(r))+(1)/(3^(r))+"…."+(1)/(2008^(r))`. Find `sum_(k=2)^(oo) f(k)`

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The correct Answer is:
`2007/2008`
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