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Consider Sn=1/(3^2+1)+1/(4^2+2)+1/(5^2+3...

Consider `S_n=1/(3^2+1)+1/(4^2+2)+1/(5^2+3)+1/(6^2+4)+,,,` upto n terms then

A

general term of the series is `t_(n) = (1)/(n^(2) + 5n + 4)`

B

general term of the series is `t_(n) = (1)/(n^(2) - 5n + 4)`

C

`S_(oo) = 13/36`

D

`S_(oo) = 15/36`

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The correct Answer is:
A
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