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In the binomial expansion of `(a-b)^nngeq5,` the sum of the 5th and 6th term is zero. Then `a//b` equals `(n-5)//6` b. `(n-4)//5` c. `n//(n-4)` d. `6//(n-5)`

A

`(n-5)/(6)`

B

`(n-4)/(5)`

C

`(5)/(n-4)`

D

`(6)/(n-5)`

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The correct Answer is:
A
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