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If sum(r=0)^(n) (-1)^(r ).""^(n)C(r)[(1)...

If `sum_(r=0)^(n) (-1)^(r ).""^(n)C_(r)[(1)/(2^(r))+(3^(r))/(2^(2r))+(7^(r))/(2^(3r))+"……..""to m terms"] = k(1-1/(2^(mn)))` , then k =

A

`(1)/(2^(n) - 1)`

B

`(1)/(2^(2n) - 1)`

C

`(1)/(2^(mn) + 1)`

D

`(1)/(2^(n) +1)`

Text Solution

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The correct Answer is:
A
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