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If sum(r=0)^(2n) a(r)(x-1)^(r) = sum(r=0...

If `sum_(r=0)^(2n) a_(r)(x-1)^(r) = sum_(r=0)^(2n) b_(r)(x-2)^(r)` and `b_(r) = (-1)^(r-n)` for all `r ge n`, then `a_(n)`=

A

`.^(2n+1)C_(n-1)`

B

`.^(3n)C_(n)`

C

`.^(2n+1)C_(n)`

D

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The correct Answer is:
A
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