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The vertices of a triangle are `A(x_1,x_1 tan alpha), B (x_2,x_2 tan Beta) and C(x_3, x_3 tan gamma)`. If the circumcentre of `DeltaABC` coincides with the origin and H (a, b) be its orthocentre, then `a/b` is equal to

A

`(x_(1) + x_(2) + x_(3))/(x_(1) tan alpha + x_(2) tan beta + x_(3) tan gamma)`

B

`(x_(1) cos alpha + x_(2) cos beta + x_(3) cos gamma)/(x_(1)sinalpha + x_(2)sin beta +x_(3) sin gamma)`

C

`(tanalpha + tanbeta +tangamma)/(tan alpha. tanbeta . tan gamma)`

D

`(cosalpha+cosbeta+cosgamma)/(sinalpha+sinbeta+singamma)`

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The correct Answer is:
A
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