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If S(n) = sum(r=0)^(n) (1)/(""^(n)C(r)) ...

If `S_(n) = sum_(r=0)^(n) (1)/(""^(n)C_(r))` and `t_(n) =sum_(r=0)^(n) (r )/(""^(n)C_(r))`, then `(t_(n))/(s_(n))` is equal to -

A

`n/2`

B

`n/2 - 1`

C

`n- 1`

D

`(2n-1)/(2)`

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The correct Answer is:
A
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