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Find the sum of the series (2^2-1)(6^2-1...

Find the sum of the series `(2^2-1)(6^2-1)+(4^2-1)(8^2-1)+...+(100^2-1)(104^2-1)`

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The correct Answer is:
`1/10[99.101.103.105.107+1.3.5.7]`
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