Passage of electricity through dil `H_2SO_4` for 1 hour liberates a total of 224 ml of `H_2` at S.T.P. The magnitude of current would be :-

The passage of electricity through dil H_(2)SO_(4) for 16 minutes liberates a total of 224 ml of H_(2) . The strength of the current in ampres will be

The sam quantity of electricity is passed through H_2 SO_4 and HCI solutins of same concentration. The amount of hudrogen liberated from H_2SO_4 as cmpared to that from HCI is.

Assertion: 65.38 g of Zn when treated with excess of dilute H_2SO_4 , will always form 22.4 L of H_2 at S.T.P. Reason: The yield of a product is always in accordance with the stoichiometry of the reaction.

Which liberates SO_2 with dil. H_2SO_4 ?

Complete the reaction: Fe(s)+dil H_2SO_4rarr

24 grams of metal reacts with an acid and liberated 22.4 lit of hydrogen at S.T.P. The eq.mass of metal is