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Structure of N(2)O is N = N = O. Calcula...

Structure of `N_(2)O` is `N = N = O`. Calculate bond enthalphy of `N = N` bond in `N_(2)O`.
Given : `{:(DeltaH_(f,N_(2)O)^(@)=100 "kJmol"^(-1)" "BE_(N=N)=950 kJ mol^(-1)),(BE_(N=0)=600 "kJmol"^(-1)" "BE_(O=O)=500 "kJmol"^(-)):}`
and resonance energy of `N_(2)O = - 100 kJ mol^(-1)`

A

`500 kJ mol^(-1)`

B

`450 kJ mol^(-1)`

C

`400 kJ mol^(-1)`

D

`420 mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
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Find bond enthalpy of C=O (in kJ/mol) using following information : DeltaH_("atomisation")[C(s)]=700 kJ/mol DeltaH_(f)[CO_(2)(g)]=-400 kJ/mol BE_(o=o=500 kJ/mol Resonance energy of CO_(2)=-150 kJ/mol