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At t = 2 sec., a particles is at (1,0,0,...

At t = 2 sec., a particles is at `(1,0,0,).` It moves towards `(4,4,12)` with a constant speed of 65 m/s. The position of the paritcle is measured in metres and the time is sec. Assuming constant velocity, the position of the particle at t = 3 s is,

A

`(13hati-120hatj+40hatk)`

B

`(40hati+31hatj-120hatk)`

C

`(13hati-40hatj+12hatk)`

D

`(45hati+60hatj+180hatk)`

Text Solution

Verified by Experts

The correct Answer is:
D
`vecS=vecVt`
`vecr_(f)-hati=(65(3hati+4hatj+12hatk))/(13)xx3`
`vecr_(f)=46veci+60vecj+180veck`
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