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Statement-1: Each point on the line 7x-y...

Statement-1: Each point on the line `7x-y=0` is equidistant from the lines
`4x+3y-1=0" and "3x-4y+1=0`
Statement-2: The locus of point which is equidistant from 2 given lines `L_(1)-=a_(1)x+b_(1)y+c_(1)=0` and `L_(2)-=a_(2)x+b_(2)y+c_(2)=0` need not always be the angle bisector of 2 given lines.

A

Statement-1 is true, statement-2 is true and statement-2 is correct explanation for statement-1 .

B

Statement-1 is true, statement-2 is true and statement-2 is NOT the correct explanation for statement-1.

C

Statement-1 is true, statement-2 is false.

D

Statement-1 is false, statement-2 is true.

Text Solution

Verified by Experts

The correct Answer is:
A

`(4x+3y-1)/(5) = +- ((3x-4y+1)/(5))`
The 2 angle bisectors are :
`x+7y-2 =0`
`7x-y = 0`
Statement-2 is correct as the lines can be parallel also.
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