Home
Class 12
MATHS
An electric field given by vec(E)=4hat(i...

An electric field given by `vec(E)=4hat(i)+3(y^(2)+2) hat(j)` pierces a gaussian cube of side 1m placed at origin such that one of its corners is at origin and rest of sides are along positive side of coordinate axis. Find the magnitude of net charge enclosed within the cube
`[3 in_(0)]`

Text Solution

Verified by Experts

`"Along z axis "vec(E)*dvec(A)=0`
`"Along x axis "vec(E)=cont`.
`:.phi_(x)=0`
for y=0
`fvec(E)*dvec(A)=f3(0+2)hat(j)*dA(-hat(j))=6fdA=-6`
for y=1
`fvec(E)*dvec(A)=f3(1+2)hat(j)*dA(hat(j))=9fdA=9`
`:.phi_("net")=+3 in_(0)]`
Promotional Banner

Topper's Solved these Questions

  • TEST PAPERS

    BANSAL|Exercise CHEMISTRY SECTION-2 PART-A [SINGLE CORRECT CHOICE TYPE]|9 Videos

  • TEST PAPERS

    BANSAL|Exercise CHEMISTRY SECTION-2 PART-A [MULTIPLE CORRECT CHOICE TYPE]|5 Videos

  • TEST PAPERS

    BANSAL|Exercise PHYSICS SECTION - 1 PART-B [MULTIPLE CORRECT CHOICE TYPE]|5 Videos

  • PROBABILITY

    BANSAL|Exercise All Questions|1 Videos

  • THERMODYNAMICS

    BANSAL|Exercise Match the column|7 Videos

Similar Questions

Explore conceptually related problems

An electric field given by vec(E )= 4hat(i)+3(y^(2)+2)hat(j) pieces Gaussian cube side 1m placed at origin such that is three sides represents x,y and z axis. This net charge enclosed within the cube is

An electric field given by vec(E) = 4hat(i) - (20 y^(2) + 2) hat(j) pierces a Gussian cube of side 1 m placed at origin such that its three sides represents x,y and z axes. The net charge enclosed within the cube is x xx 10^(-10)C , where is _____. (take in_(0) = 8.85 xx 10^(-12) N^(-1)m^(-2)C^(2) )

In space electric field is given by vec(E) = 150 y^2 J N/C . A cube of side 0.5m is placed with one corner at origin along + y axis. Find charge enclosed inside cube:

An electric field vec(E)=(10 hat(i) + 20 hat(j)) N//C exists in the space. If the potential at the origin is taken to be zero, find the potential at (3m, 3m).

Electric field in a region is given by vec(E)=-4xhat(i)+6yhat(j) . The charge enclosed in the cube of side 1 m oriented as shown in the diagram is given by alpha in_(0) . Find the value of alpha .

A non-uniform electric field E=(5xhat i+3hat j)N/C goes through a cube of side length 2.0m oriented as shown. Then,

A cube is placed inside an electric field, vec E = 150 y^2 hatj . The side of the cube is 0.5 m and is placed in the field as shown in the given figure. The charge inside the cube is :

A cube is placed inside an electric field, vec E = 150 y^2 hatj . The side of the cube is 0.5 m and is placed in the field as shown in the given figure. The charge inside the cube is :