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If g is the acceleration due to gravity on the earth's surface the change in the potential energy of an object of mass m raised from the surface of the eacrth to height to the radius R of the earth is

A

`mgR//2`

B

2mgR

C

mgR

D

#REF!

Text Solution

Verified by Experts

The correct Answer is:
A

`u_(g)=-(GM_(1)M_(2))/(R)`
`rArr" "u_(f)-u_(i)=-(GMm)/(2R)=(GMm)/(R)`
`Deltau=(GMm)/(2R)=(GMm)/(R)" "{g=(GM)/(R^(2))}`
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