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The reaction (3)^(7)Li+(1)^(1)H rightarr...

The reaction `_(3)^(7)Li+_(1)^(1)H rightarrow _(4)^(7)Be + _(0)^(1)n` is endothermic. Assuming that Li nuclei is free and at rest. What is the minimum kinetic energy ( in keV) of incident proton so that this reaction occurs? Take Q value of this reaction as -1645 keV.

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Verified by Experts

The correct Answer is:
`0004`

Energy available `=(1)/(2) mu v_(rel)^(2).=Q` value.
`(1)/(2)xx(7xx1)/(7+1)xxv_(rel)^(2)=Q` value.
`rArr (1)/(2)xxv_(rel)^(2)=Qxx(8)/(7)`
`K_(i)1645xx(8)/(7)=1880`KeV
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