If one end of a diameter of the circle `2x^(2)+2y^(2)-4x-8y+2=0` is (-1,2), then the other end of the diameter is

If one end of a diameter of the circle 2x^(2)+2y^(2)-4x-8y+2=0 is (3,2), the other end is

If one end of the a diameter of the circle 2x^(2)+2y^(2)-4x-8y+2=0 is (3,2), then find the other end of the diameter.

If one end of the diameter of the circle 2x^2+2y^2-4x-8y+2=0 is (3,2), then find the other end of the diameter.

If one end of the diameter of the circle 2x^2+2y^2-4x-8y+2=0 is (3,2), then find the other end of the diameter.

If one end of the a diameter of the circle 2x^2+2y^2-4x-8y+2=0 is (3, 2), then find the other end of the diameter.

If one end of the diameter of the circle x^(2)+y^(2)-6x+4y-12=0" is "(7,-5) then the other end of the diameter is

If one end of a diameter of the circle 3x^(2)+3y^(2)-9x+6y+5=0 is (1,2), then the other end is

If one end of a diameter of the circle 3x^(2)+3y^(2)-9x+6y+5=0 is (1, 2), then the other end is

If one end of diameter of the circle 2x^2+2y^2-4x-8y+2=0 is (3,2) , then the other end is :

If one end of a diameter of a circle 2x^2 + 2y^2 - 4x - 8y + 2 = 0 is (3,2), then the other end is