A proton moving in a perpendicular magnetic field possesses kinetic energy E . The magnetic field is increased 8 times. But the proton is constratined to move in the path of same radius. The radius energy will increase.

A particle moving in a magnetic field increases its velocity, then its radius of the circle

A proton is moved along a magnetic field line.The magnetic force on the particle is

A proton is rotating along a circular path with kinetic energy K in a uniform magnetic field B. If the magnetic is made four times, the kinetic energy of rotation of proton is

A proton is moving along Z -axis in a magnetic field. The magnetic field is along X -axis. The proton will experience a force along

A proton of mass m and charge q is moving in a plane with kinetic energy E. if there exists a uniform magnetic field B, perpendicular to the plane motion. The proton will move in a circular path of radius

A proton is moving perpendicular to the magnetic field with speed v and it is found that the proton takes T time to complete its circular path once. If the speed of the particle is increased to 2v, then how much time will it take to complete the circle?

An electron and a proton have equal kinetic energies. They enter in a magnetic field perpendicularly, then

(a) An electron moves along a circle of radius 1m in a perpendicular magnetic field of strength 0.50 T. What would be its speed? Is it reasonable?(b) If a proton moves along a circel of the same radius in the same magnetic field, what would be its speed?