The vectors `vecA` has a magnitude of 5 unit `vecB` has a magnitude of 6 unit and the cross product of `vecA and vecB` has a magnitude of 15 unit. Find the angle between `vecA and vecB`.

Vector vecA has a magnitude of 6.00 vector vecB has a magnitude of 7. 00 units, and vecA.vecB has a value of 14.0 What is the angle between the direction of vecA and vecB ?

Two vectors vecA and vecB have magnitude in the ratio 1:2 respectively. Their difference vector has as magnitude of 10 units, and the angle between vecA & vecB is 120^(@) . The magnitude of vecA and vecB are :

Two vectors vecA and vecB have magnitude in the ratio 1:2 respectively. Their difference vector has as magnitude of 10 units, and the angle between vecA & vecB is 120^(@) . The magnitude of vecA and vecB are :

The resultant of two vectors vecA and vecB is perpendicular to vecA and equal to half of the magnitud of vecB . Find angle between vecB and vecB ?

A magnitude of vector vecA,vecB and vecC are respectively 12, 5 and 13 units and vecA+vecB=vecC then the angle between vecA and vecB is

A magnitude of vector vecA,vecB and vecC are respectively 12, 5 and 13 units and vecA+vecB=vecC then the angle between vecA and vecB is