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( secA+tanA )( 1−sinA )= (a)secA ...

( secA+tanA )( 1−sinA )= (a)secA (b) sinA (c) cosec A (d) cosA

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Choose the correct option.Justify your choice:(iii) (secA+tanA)(1-sinA) = a)secA b)sinA c)cosecA d)cosA

The value of [(secA+tanA)(1-sinA)] is equal to (a) tan^2A(b)sin^2A (c) cosA (d) sinA

secA(1-sinA)(secA+tanA)=1

Prove that : (secA+tanA)(1-sinA)=cosA

Prove that : (secA+tanA)(1-sinA)=cosA

Prove that : (secA+tanA)(1-sinA)=cosA

Prove: (secA-tanA)^2=(1-sinA)/(1+sinA)

(tanA+secA-1)/(tanA-secA+1)=(1+sinA)/(cosA)

(tanA+secA-1)/(tanA-secA+1)=(1+sinA)/(cosA)

(1+cotA+tanA)(sinA-cosA)=(secA)/(cosec^2A)-(cosecA)/(sec^2A)