The diameter of an objective of a telescope, which can just resolve two stars situated at angular displacement of `10^(-4)` degee, should be `(lambda = 5000 Å)`

The diameter of an object of a telescope, which can just resolve two stars situated an angular displacement of 10^(-4) degree, should be ( lambda =5000 A^(@) )

What should be the size of the aperture of the objective of telescope which can just resolve the two stars of angular width of 10^(3) degree by light of wavelength 5000 Å ?

The diameter of objective of a telescope is 1m . Its resolving limit for the light of wave length 4538 Å , will be

Calculate the aperture of the objective of a telescope which may be used to just resolve two stars separated by 6.1 times 10^-6 radian, if light from the star has a wavelength of 550 nm.

The diameter of the objective of a telescope is 10 cm . The telescope is situated at a distance of 1 km from two objective . If average wave length of the light is 5000 "Å" , then to resolve these two object, what will be the minimum distance between the two ?

Diameter of the objective of a telescope is 200cm. What is the resolving power of a telescope? Take wavelength of light =5000Å.

Diameter of the objective of a telescope is 200cm. What is the resolving power of a telescope? Take wavelength of light =5000Å.

Diameter of the objective of a telescope is 200 cm. What is the resolving power of a telescope ? Take wavelength of light =5000 Å .